Python Cost Model

Python is a high-level programming language, with many powerful primitives. Analyzing the running time of a Python program requires an understanding of the cost of the various Python primitives.

For example, in Python, you can write:

    L = L1 + L2

where L, L1, and L2 are lists; the given statement computes L as the concatenation of the two input lists L1 and L2. The running time of this statement will depend on the lengths of lists L1 and L2. (The running time is more-or-less proportional to the sum of those two lengths.)

Our goal in this section is to review various Python primitive operations, and to determine bounds and/or estimates on their running times. Our approach will involve both a review of the relevant Python implementation code, and also some experimentation (analysis of actual running times and interpolating a nice curve through the resulting data points).

Python Running Time Experiments and Discussion

The running times for various-sized inputs were measured, and then a least-squares fit was used to find the coefficient for the high-order term in the running time. (Which term is high-order was determined by some experimentation; it could have been automated...)

The least-squares fit was designed to minimize the sum of squares of relative error, using scipy.optimize.leastsq.

(Earlier version of this program worked with more than the high-order term; they also found coefficients for lower-order terms. But the interpolation routines tended to be poor at distinguishing n and n lg n. Also, it was judged to be more interesting to work with relative error than with absolute error. Finally, it seemed that looking at only the high-order term, and studying only the relative error, seemed simplest.)

The machine used was an IBM Thinkpad T43p with a 1.86GHz Pentium M processor and 1.5GB RAM.

[This output may have results somewhat different than in the charts below, due to random run-time variations...]

 

Cost of Python Integer Operations
x,y, and z are n-bit numbers, w is an 2n-bit number, s is an n-digit string
Convert string to integer int(s) 84 * (n/1000)^2 microseconds n <= 8000 6% rms error
Convert integer to string str(x) 75 * (n/1000)^2 microseconds n <= 8000 3% rms error
Convert integer to hex "%x"%x 2.7 * (n/1000) microseconds n <= 64000 19% rms error
Addition (or Subtraction) x+y 0.75 * (n/1000) microseconds n <= 512000 8% rms error
Multiplication x*y 13.73 * (n/1000)^1.585 microseconds n <= 64000 10% rms error
Division (or Remainder) w/x 47 * (n/1000)^2 microseconds n <= 32000 6% rms error
Modular Exponentiation pow(x,y,z) 60000 * (n/1000)^3 microseconds n <= 4000 8% rms error
n-th power of two 2**n 0.06 microseconds n <= 512000 10% rms error

It is perhaps curious that multiplication is implemented using Karatsuba's algorithm, giving an Θ(nlg 3) running time, while division uses an Θ(n2) algorithm.

 

Cost of Python String Operations
s and t are length-n strings, u is length (n/2)
Extract a byte from a string s[i] 0.13 microseconds n <= 512000 29% rms error
Concatenate s+t 1 * (n/1000) microseconds n <= 256000 19% rms error
Extract string of length n/2 s[0:n/2] 0.3 * (n/1000) microseconds n <= 256000 28% rms error
Translate a string s.translate(s,T) 3.2 * (n/1000) microseconds n <= 256000 11% rms error

 

Cost of Python List Operations
L and M are length-n lists, P has length n/2
Create an empty list list() 0.40 microseconds (n=1) .5% rms error
Access L[i] 0.10 microseconds n <= 640000 3% rms error
Append L.append(0) 0.24 microseconds n <= 640000 3% rms error
Pop L.pop() 0.25 microseconds n <= 64000 0.5% rms error
Concatenate L+M 22 * (n/1000) microseconds n <= 64000 3% rms error
Slice extraction L[0:n/2] 5.4 * (n/1000) microseconds n <= 64000 4% rms error
Copy L[:] 11.5 * (n/1000) microseconds n <= 64000 10% rms error
Slice assignment L[0:n/2] = P 11 * (n/1000) microseconds n <= 64000 4% rms error
Delete first del L[0] 1.7 * (n/1000) microseconds n <= 64000 4% rms error
Reverse L.reverse() 1.3 * (n/1000) microseconds n <= 64000 10% rms error
Sort L.sort() 0.0039 * n lg(n) microseconds n <= 64000 12% rms error

The first time one appends to a list, there is additional cost as the list is copied over and extra space, about 1/8 of the list size, is added to the end. Whenever the extra space is used up, the list is re-allocated into a new array with about 1.125 the length of the previous version.

 

Cost of Python Dictionary Operations
D is a dictionary with n items
Create an empty dictionary dict() 0.36 microseconds (n=1) 0% rms error
Access D[i] 0.12 microseconds n <= 64000 3% rms error
Copy D.copy() 57 * (n/1000) microseconds n <= 64000 27% rms error
List items D.items() 0.0096 * n lg(n) microseconds n <= 64000 14% rms error

What should the right high-order term be for copy and list items? It seems these should be linear, but the data for both looks somewhat super-linear. We've modelled copy here as linear and list items as n lg(n), but these formulae need further work and exploration.