]>
|
Home | 18.013A | Chapter 14 |
||
|
|
||
A curve in three dimensions can be defined by two equations (that is as the intersection of two surfaces) or by use of a single parameter as in two dimensions.
If is an extreme values of on we cannot have non-zero at argument , by our general principle; otherwise will be larger on one side of and smaller on the other than its value at on .
The implications of this condition are different here however. We can no longer say that points in some particular direction at an extremal point. Rather it must be normal to some particular direction, that of the tangent vector to at such points.
When is described by two equations, and is in the direction of , and the statement that has no component in that direction is the statement that lies in the plane of and and so the volume of their parallelepiped is 0 and the determinant whose columns are all these grads must be 0.
This condition and and determine and at critical points.
Another way to state the same condition is to use two Lagrange Multipliers, say and and write . We can solve the three equations obtained by writing all three components of this vector equation and use them and and , to solve for , and .
Exercises:
14.6 Given a curve defined as the intersection of the surfaces defined by equations , and , find equations determining the critical points of by the determinantal approach.
14.7 Write the equations for the critical points obtained using the Lagrange Multipliers approach for the same problem.
14.8 We seek the critical points for
on the curve
, for
to
, with
. Write equations for them.
|
|